Factoring

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YFO008

Mathematics

Description

Eyiafiallajokull is a volcano in Iceland.

During a recent eruption, the volcano spewed out copious amounts of ash.

One small piece of ash was ejected from the volcano with an ininitial velocity of 368 ft/sec.

The height H, in feet, of our ash projectile is given by the equation:

H = -16ft^2 + 368t,

where t is the time, in seconds.

The graph of this equation will be parabola.

We will assume that the volcano has no height.

i.e H = 0 at t = 0.

Question 1)

When does the ash projectile read its maximum height?

Question 2)

What is its maximum height?

Question 3)

When does the ash projectile return to the ground?

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We will assume that no has no heig! 11 • i.e. H= 0 at t = 0. t t=0, H=0 11 到 1:16 12:28 Rasmussen Personal Support Center, call toll-free, 24/7: 1-866-693-2211 Copyright © 2017 Rasmussen College, Inc. All rights reserved. Coursed: SPR1711-ONP-MAT1222-03 (PK1: _19621_1) nade in:00500000 / PK1: 35913_1) 34 Assignments - MAT12...x Lesson Content - B279/MA X + vebapps/blackboard/content/listContent.jsp?course_id=_19621_1&content_id=_1671106_1 Q Search hen H H = ? 2) What is its maximum height? t 1:34 12:28 Rasmussen Personal Support Center, call toll-free, 24/7:1-866-693-2211 Copyright © 2017 Rasmussen College, Inc. All rights reserved Courselb: SPR17T1-ONP-MAT1222-03 (PK1: _19621_1) Username: brittania larson@smail rasmussen.edu (ID: 00500000 / PK 1: __35913_11 Server OPRCBBLVVB04 Need help? Assignments - MAT1222 S... X Ble lesson content - Berm X edu/webapps/blackboard/content/listContent.jsp?course_id=_19621_1&content_id=_1671106_1 c Q Search - CBSS... 众自 H Н t = ? 1) When does the ash projectile read maximum height? 1 t Rasmussen Personal Support Center, call toll-free, 24/7:1-866-693-2211 Copyright © 2017 Rasmussen College, Inc. All rights reserved. 1222fw_Spring_17/5_72.html# Coursed: SPR17T1-ONP-HAT1222-03 (PK1: 19621 1; Username: brittania.larson@smail.rasmussen.edu (ID: 00500000 PK1: _35913_1) Server: OPROBBLVB04 Need help?
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Explanation & Answer

The solution is ready.

𝐻(𝑡) = −16𝑡 2 + 368𝑡 = 16𝑡(23 − 𝑡).

1. The graph is a parabola branches...


Anonymous
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