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QUESTION 12 Use the given conditions to write an equation for the line in the indicated form. 1 Passing through (5, 3) and perpendicular to the line whose equation is y = 5x + 5; slope-intercept form O y= - 7x + 38 O y = 7x - 38 O y = - 7x - 38 1 y- oo QUESTION 13 Use the given conditions to write an equation for the line in the indicated form. Passing through (2, 1) and parallel to the line whose equation is y = -2x + 3 : point-slope form y - 1 = -2(x - 2) y - 2 - -2(x - 1) y = 2x m) y - 1 = X-2 QUESTION 14 QUESTION 14 Given functions f and g, perform the indicated operations. f(x) = 4x - 7, g(x) = 2x - 5 Find f-8 O -2x + 2 C 6x - 12 O 2x - 12 2x - 2 QUESTION 15 Given functions f and g, perform the indicated operations. f(x) = 5x2 - 9x, g(x) = x2 - 4x - 45 f Find 8 05-x o c c 5x2 - 9x x2 - 4x - 45 For the given functions f and g, find the indicated composition. f(x) = -4x + 2, g(x) = 5x + 8 (gºf)(x) -20x + 18 -20x + 34 20x + 18 O -20% - 2 QUESTION 17 For the given functions f and g, find the indicated composition. f(x) = -2x + 5, g(x) = 5x + 9 (gºf)(x) 0 -10x + 23 0 -10x + 34 10x + 34 0 -10x - 16 QUESTION 18 Find the inverse of the one-to-one function. f(x) = f1(x) - 1168) = 5* - 2 QUESTION 24 Determine whether the given quadratic function has a minimum value or maximum value. Then find the coordinates of the minimum or maximum point. f(x) = -x2 - 2x + 2 minimum; (-1,3) O maximum; (3, -1) minimum; (3. - 1) maximum;( - 1,3) QUESTION 25 Determine whether the given quadratic function has a minimum value or maximum value. Then find the coordinates of the minimum or maximum point. f(x) = 2x2 - 2x - 3 O 7 minimum; 22 maximum; N-01NNNN IN 7 maximum; 2 7 minimum; ESTION 26 Use the graph of f(x) = 4% to obtain the graph of g(x) = 4-X 6 -4 ot -6 2 4 4. 17 4 + 6 37. Click Save and Submit to save and submit. Click Save All Answers to save all answers.
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Question 12:
Perpendicular lines have slopes that are opposite (change the sign) reciprocals of each other. The slope
of the given line is 1/7. That means a line that is perpendicular will have a slope of -7.
Now use point slope form to determine a line with a slope of -7 that also contains the given point.
y− y 1= m( x− x 1)
y− 3= − 7( x− 5)
y− 3= − 7x+ 35
y= ...


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