Exponential and Logarithmic Functions

User Generated

znlnq42

Mathematics

Description

file down below

Unformatted Attachment Preview

Unit 6 Project 1. 2. 3. 4. Write 3​7​ = 2187 in logarithmic form. Write log​8​ 16 = (4/3) in exponential form. Express log​3​ 5 in terms of common logarithms. Then approximate its value to four decimal places. Evaluate log​2​(1/64). Use log​4​ 7 β‰ˆ 1.4037 and log​4​ 3 β‰ˆ 0.7925 to approximate the value of each expression. 5. 6. log​4​ 21 log​4​ (7/12) Solve each equation or inequality. Round to four decimal places if necessary. 7. 8. 9. 10. 11. 27​2​p​ + 1​ = 3​4​p​ Β­ 1 log​m​ 144 = Β­2 2​e3​​ x​ + 5 = 11 log​9​ (​x​ + 4) + log​9​ (​x​ Β­ 4) = 1 log​2​ ​x​ < 7 Use the following information for questions 13Β­14. You buy a commemorative coin for $20. The value of the coin increases at a rate of 3.5% per year. 12. 13. How much will the coin be worth in 15 years? After how many years will the coin have doubled in value? 14. Radioactive iodine is used to determine the health of the thyroid t​ gland. It decays according to the equation ​y​ = ​aeΒ­0.0856​ ​ , where ​t​ is in days. Find the halfΒ­life of this substance.
Purchase answer to see full attachment
User generated content is uploaded by users for the purposes of learning and should be used following Studypool's honor code & terms of service.

Explanation & Answer

Here are the answers, please tell me if you have any problem

1- π‘™π‘œπ‘”3 2187 = 3
4

2- 83 = 16
3- π‘™π‘œπ‘”3 5 =
4- π‘™π‘œπ‘”2

1
64

π‘™π‘œπ‘”10 5
π‘™π‘œπ‘”10 3

=

= π‘™π‘œπ‘”2 64

log 5

log 3
βˆ’1

= 𝟏. πŸ’πŸ”πŸ’πŸ—πŸ• β‰… 𝟏. πŸ’πŸ”πŸ“πŸŽ

= π‘™π‘œπ‘”2 (26 )βˆ’1 = π‘™π‘œπ‘”2 2βˆ’6 = βˆ’6 π‘™π‘œπ‘”2 2 = βˆ’πŸ”

5- π‘™π‘œπ‘”4 21 = π‘™π‘œπ‘”4 (3 Γ— 7) = π‘™π‘œπ‘”4 3 + π‘™π‘œπ‘”4 7 = 0.7925 + 1.4037 =
𝟐. πŸπŸ—πŸ”πŸ
6- π‘™π‘œπ‘”4 (7/12) = π‘™π‘œπ‘”4 7 βˆ’ π‘™π‘œπ‘”4 12 = π‘™π‘œπ‘”4 7 βˆ’ π‘™π‘œπ‘”4 (3 Γ— 4) =
π‘™π‘œπ‘”4 7 βˆ’ (π‘™π‘œπ‘”4 3 + (π‘™π‘œπ‘”4 4) = 1.4037 βˆ’ (0.7925 + 1) =
βˆ’πŸŽ. πŸ‘πŸ–πŸ–πŸ–
7- 272𝑝+1 = 34π‘βˆ’1
(33 )2𝑝+1 = 34π‘βˆ’1
33(2𝑝+1) = 34π‘βˆ’1
36𝑝+3 = 34π‘βˆ’1
6p+3 = 4p-1
2p = -4
P= -2
8- π‘™π‘œπ‘”π‘š 144 = βˆ’2 converting to the exponential...


Anonymous
Just what I was looking for! Super helpful.

Studypool
4.7
Trustpilot
4.5
Sitejabber
4.4

Related Tags