Description
- Compute the weighted mean for the following data.
Question 2
- If P(A) = 0.50, P(B) = 0.40, and P(A ∪ B) = 0.88, then P(B | A) =
Question 3
Six vitamin and three sugar tablets identical in appearance are in a box. One tablet is taken at random and given to Person A. A tablet is then selected and given to Person B. What is the probability that
- Person A was given a vitamin tablet?
- Person B was given a sugar tablet given that Person A was given a vitamin tablet?
- neither was given vitamin tablets?
- both were given vitamin tablets?
- exactly one person was given a vitamin tablet?
- Person A was given a sugar tablet and Person B was given a vitamin tablet?
- Person A was given a vitamin tablet and Person B was given a sugar tablet?
Explanation & Answer
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Question 1.
Xi
wi
wx
19
12
228
17
30
510
14
28
392
13
10
130
18
10
180
Ʃxi=81
Ʃwi=90
Ʃwx=1440
Weighted mean= Ʃwx / Ʃwi
1440/90= 16
Question 2
P (A) =0.50
P (B) =0.40
P (A U B) =0.88
Addition rule is applied to solve the problem
P (A U B) = P (A) + P (B) – P (A) P (B/A)
0.88= 0.5+0.4 – 0.5 P (B/A)
0.88= 0.9-0.5 P (B/A)
0.02/0.5=0.5/ P (B/A)
P (B/A) = 0.04
...
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