Write out conversion factors between the moles of each element and the moles of the compound C5H12

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Chapter 6

Conversion Factors

1. Write out conversion factors between the moles of each element and the moles of the compound C5H12


2. Write out the conversion factor of the given element in the given compound using the mass percent composition

a) Carbon dioxide is 27.19% carbon by mass

b) Butane is 17.34% hydrogen by mass

c) C6H8O7 is 58.29% oxygen by mass

The Mole Concept

3. How many moles of atoms are in the following?

a) 8.22 x 1024 As atoms

b) 4.41 x 1022 Ne atoms

c) 6.77 x 1023 Li atoms

d) 2.10 x 1021 S atoms

4. How many atoms are in the following given numbers of moles of an element?

a) 0.994 mol F

b) 4.39 mol Sr

c) 9.1 x 10-3 mol B

d) 13.8 mol Cl

5. Complete the table:

6. Calculate the mass in grams of the following:

a) 4.45 x 1019 Ag atoms

b) 5.50 x 1024 Bi atoms

c) 2.08 x 1021 Se atoms

d) 7.31 x 1024 Ar atoms

7. Calculate the number of atoms in each of the following:

a) 14.8g Al

b) 3.98g Ca

c) 1.90g Co

d) 26.7g S

8. Complete the table:

9. Calculate the mass of the following in grams:

a) 6.10 mol carbon monoxide

b) 0.364 mol sulfur hexafluoride

c) 4.44 mol potassium hydroxide

d) 1.71 mol lithium nitrate

10. Complete the table:


11. Calculate the number of molecules of the following:

a) 13.2g SO2

b) 9.03g CH4

c) 0.00888g H2

d) 157g LiBr


12. A sample of C6H6 has a mass of 15ng. Calculate the number of formula units.



Chemical Formulas as Conversion Factors

13. Calculate the number of moles of O in the following:

a) 11.4 mol CO2

b) 0.761 mol H2O

c) 4.08 mol N2O5

d) 0.302 mol HNO3


14. How many moles of H are in 1.85 mol [Cr(OH2)5Cl] Cl•H2O?


15. Calculate the mass in kg of the following which each contain 3.5 x 102 kg of lithium.

a) Li2SO4

b) LiOH

c) LiBr

16. Which of the following contains the greatest number of moles of oxygen? Show all work.

a) 3.03 mol C2H6O2

b) 16.9 mol N2O3

c) 8.27 mol Sr(NO3)2

d) 0.0180 mol BaSO4

Mass Percent Composition

17. A 8.91g sample of an organic compound is found to contain 3.34g C, 0.98g H, 2.61g O, and 1.98g N. Determine the mass percent of each element.

18. BaSO4 is approximately 58.84% barium by mass. Calculate the mass of barium in grams in a 7.22g sample of BaSO4.

19. Calculate the mass percent composition of oxygen in the following compounds.

a) CrO3

b) SO2

c) NaOH

d) Al2(SO4)3


20. Calculate the mass percent composition of all the individual elements in each of the following compounds.

a) HClO3

b) AgBr

c) PbSO4

d) CH4


Calculating Empirical Formulas

21. An organic compound is found to have 36.03g of carbon, 6.048g hydrogen, and 16.00g oxygen. Determine the empirical formula of the organic compound.

22. The nonsteroidal anti-inflammatory drug Ibuprofen consists of 75.69% carbon, 8.80% hydrogen, and 15.51% oxygen. Determine the empirical formula of ibuprofen.

Calculating Molecular Formulas

23. Determine the molecular formula of each of the following using the given empirical formulas and total molar masses.

a) CO2H, 225.09g/mol

b) CClN, 184.41g/mol

c) C2H3O, 86.09g/mol

d) C4H8O, 144.21g/mol

Challenge Problems

24. How many ethanol molecules are in a 613mL container of pure ethanol? Ethanol has a density of 0.7893 g/cm3.

25. Aldrin is an insecticide that was commonly used in soil fields until it was banned in many counties. It is found to consist of 39.50% carbon, 2.21% hydrogen, and 58.29% chlorine. Its molar mass is 364.884g/mol. Using this information, determine the molecular formula of Aldrin.

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Explanation & Answer

Hi, please use this file. There is small change in question (2)

CHAPTER 6:
Conversion Factors
1) Write out conversion factors between the moles of each element and the moles of the
compound 𝐶5 𝐻12
Answer:
1 mole of 𝐶5 𝐻12 consist 5 moles of 𝐶 atom and 12 moles of 𝐻 atom.
Conversion factor for Carbon and Hydrogen element are as follows:
5 𝑚𝑜𝑙𝑒𝑠 𝑜𝑓 𝐶

Number of Carbon atom (C) = 1 𝑚𝑜𝑙𝑒 𝑜𝑓 𝐶

5 𝐻12

× 𝑁𝑢𝑚𝑏𝑒𝑟 𝑜𝑓 𝑚𝑜𝑙𝑒𝑠 𝑜𝑓 𝐶5 𝐻12

12 𝑚𝑜𝑙𝑒𝑠 𝑜𝑓 𝐻

Number of Hydrogen atom (H) = 1 𝑚𝑜𝑙𝑒 𝑜𝑓 𝐶

5 𝐻12

× 𝑁𝑢𝑚𝑏𝑒𝑟 𝑜𝑓 𝑚𝑜𝑙𝑒𝑠 𝑜𝑓 𝐶5 𝐻12

2) Write out the conversion factor of the given element in the given compound using the
mass percent composition
a) Carbon dioxide is 27.19% carbon by mass
b) Butane is 17.34% hydrogen by mass
c) 𝐶6 𝐻8 𝑂7 is 58.29% oxygen by mass
Answer:
a) Molar mass of 𝐶𝑂2 = 44 g/mol
Thus, 44 g of 𝐶𝑂2 will contain =

27.19
100

× 44 ≈ 11.96 g of carbon

44

Conversion factor =11.96 ≈ 3.68
b) Molar mass of Butane = 58.12 g/mol
Thus, 58.12 g of butane will contain = 58.12 ×

17.34
100

≈ 10.08 g

58.12

Conversion factor = 10.08 ≈ 5.77
c) Molar mass of 𝐶6 𝐻8 𝑂7 = 192.12 g/mol
Thus, 192.12 g of 𝐶6 𝐻8 𝑂7 = 111.98 ×
192.12

Conversion factor = 111.98 ≈ 1.72

58.29
100

≈ 111.98 g

The Mole Concept
3) How many moles of atoms are in the following?
a) 8.22 × 1024 As atoms
b) 4.41 × 1022 Ne atoms
c) 6.77 × 1023 Li atoms
d) 2.10 × 1021 S atoms
Answer:
Number of moles of atoms =

𝑁𝑢𝑚𝑏𝑒𝑟 𝑜𝑓 𝑎𝑡𝑜𝑚𝑠
𝐴𝑣𝑜𝑔𝑎𝑑𝑟𝑜 ′ 𝑠 𝑛𝑢𝑚𝑏𝑒𝑟

=

𝑁𝑢𝑚𝑏𝑒𝑟 𝑜𝑓 𝑎𝑡𝑜𝑚𝑠
6.022×1023

8.22×1024

a) Moles of As atoms = 6.022×1023 ≈ 13.650 mol
4.41×1022

b) Moles of Ne atoms = 6.022×1023 ≈ 0.073 mol
6.77×1023

c) Moles of Li atoms = 6.022×1023 ≈ 1.124 mol
2.10×1021

d) Moles of S atoms = 6.022×1023 ≈ 0.003 mol
4) How many atoms are in the following given numbers of moles of an element?
a) 0.994 mol F
b) 4.39 mol Sr
c) 9.1 x 10-3 mol B
d) 13.8 mol Cl
Answer:
Number of atoms of an element = 𝑚𝑜𝑙𝑒𝑠 𝑜𝑓 𝑎𝑡𝑜𝑚 × 𝐴𝑣𝑜𝑔𝑎𝑑𝑟𝑜′ 𝑠 𝑛𝑢𝑚𝑏𝑒𝑟
a) Number of F atoms = 0.994 × 6.022 × 1023 ≈ 5.986 × 1023 atoms
b) Number of Sr atoms = 4.39 × 6.022 × 1023 ≈ 2.644 × 1024 atoms
c) Number of B atoms = 9.1 × 10−3 × 6.022 × 1023 ≈ 5.480 × 1021 atoms
d) Number of Cl atoms = 13.8 × 6.022 × 1023 ≈ 8.310 × 1024 atoms

5) Complete the table :

6) Calculate the mass in grams of the following:
a) 4.45 × 1019 Ag atoms
b) 5.50 × 1024 Bi atoms
c) 2.08 × 1021 Se atoms
d) 7.31 × 1024 Ar atoms
Answer:
Mass of atoms = moles of atoms × Molar mass (g/mol) of element.
⇒ Mass of atoms =

𝑁𝑢𝑚𝑏𝑒𝑟 𝑜𝑓 𝑎𝑡𝑜𝑚𝑠
𝐴𝑣𝑜𝑔𝑎𝑑𝑟𝑜 ′ 𝑠 𝑁𝑢𝑚𝑏𝑒𝑟

× 𝑀𝑜𝑙𝑎�...


Anonymous
Really helped me to better understand my coursework. Super recommended.

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