Eyjafjallajokull Projectile

Anonymous
timer Asked: Nov 5th, 2017

Question description

One small piece of ash was ejected from the volcano with an initial velocity of 368ft/sec.

The height H, in feet, of out ash projectile is given by the equation: H=-16t2^2+368t, where t is the time, in seconds.

We will assume that the volcano has no height.

H=0 at t=0

When does the ash projectile reach its maximum height? What is its maximum height? When does the ash projectile return to the ground?

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