Description
I have the answers as well. I just want you to make the report more organized and typed. Please type the hand written part
Explanation & Answer
Hello! I have attached the answer in word document for you. :) Let me know if you have any further questions.
Running head: MATLAB
1
MATLAB
Name
School
Date of Submission
MATLAB
Question 1-4
MATLAB CODE
N = 1024; % N point fft
fs = 1024; % Sample Frequency
t = (0:N-1) / fs;
%% Time Domain
% Creating a one second long message signal
fm = 50; % Hertz
Am = 1;
m = Am *sin(2*pi*fm*t); % message signal
subplot(3,1,1)
plot(t,m)
xlabel('time');
ylabel('Am*sin(2*pi*fm*t)')
title('Message Signal');
% Creating a carrier signal of duration 1 second
Ac = 1; %Carrier Amplitude
fc = 400;
c = Ac*cos(2*pi*fc*t); %c is the carrier signal
subplot(3,1,2)
plot(t,c)
xlabel('time');
ylabel(' Ac*cos(2*pi*fc*t)');
title('Carrier Signal');
% Modulating the signal by multiplying the message and carrier signal
s = m.*c; %s is the modulated signal
subplot(3,1,3)
plot (t,s);
xlabel('time');
ylabel('s = m.*c')
title('Modulated Signal');
%% Frequency Domain
% The conversion from the frequency domain to the time domain is achieved
% by the use of the fast fourier transform
N = 1024;
fs = 1024;
t = (0:N-1) / fs;
% Message Signal
fm = 50; % Hertz
Am = 1;
m = Am* cos(2*pi*fm*t); % message signal
Mf = 2/N * abs(fft(m,N));
subplot (3,1,1)
plot(t(1:1000), Mf(1:1000))
2
MATLAB
xlabel('frequency');
ylabel('Amplitude');
title('Magnitude Spectrum of Message Signal');
% Carrier Signal
Ac = 1; %Carrier Amplitude
fc = 400;
c = Ac*cos(2*pi*fc*t); %c is the carrier signal
Cf = 2/N * abs(fft(c,N));
subplot(3,1, 2)
plot(t(1:1000), Cf(1:1000))
xlabel('frequency');
ylabel('Amplitude')
title('Magnitude Spectrum of Carrier Signal');
% Modulated Signal
s = m.*c; %s is the modulated signal
Sf = 2/N * abs(fft(s,N));
subplot (3,1,3)
plot(t(1:1000), Sf(1:1000))
xlabel('frequency');
ylabel('Amplitude');
title('Magnitude Spectrum of Modulated Signal');
Question 5
Explain what you see in the spectrum of the modulated signal and how it relates to the
spectrum of the message and carrier.
Solution
Since i...
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