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Economics

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Homework3

Clearly show your calculations in all the problems. Points will not be earned if you do not show calculations.

1. The following is a payoff table giving profits for various situations.

States of Nature

Alternatives

A

B

C

Alternative 1

140

160

140

Alternative 2

220

120

70

Alternative 3

120

140

200

Do Nothing

0

0

0

What decision would a pessimist make?

2. The following is a payoff table giving profits for various situations.

States of Nature

Alternatives

A

B

C

Alternative 1

140

160

140

Alternative 2

220

120

70

Alternative 3

120

140

200

Do Nothing

0

0

0

What decision should be made based on the minimax regret criterion?

3. Dr. McFadden, a surgeon, must decide what mode of treatment to use on Mr. Samuels. There are three modes of treatment: Mode A, B, and C; and three possible states of nature: 1. Treatment succeeds, and patient leads a normal life, 2. Patient survives treatment but is permanently disabled, and 3. Patient fails to survive treatment. The probability of that the patient leads a normal life is 0.4, Disability is 0.4 and Non-survival is 0.2. Dr. McFadden has prepared the decision table below. What mode of treatment maximizes the expected value?

Treatment Mode

Outcome

EMV

Normal Life

Disability

Non-Survival

A

$1,000,000

-$2,000,000

-$500,000

B

$3,000,000

-$2,500,000

-$500,000

C

$4,000,000

-$3,000,000

-$600,000

P(outcome)

0.4

0.4

0.2

4. A plant manager considers the operational cost per hour of five machine alternatives. The cost per hour is sensitive to three potential weather conditions: cold, mild, and warm. The following table represents the operations cost per hour for each alternative-state of nature combination:

States of Nature

Weather related cost per hour

Alternatives

Cold cost/day

Mild cost/day

Warm cost/day

Machine 1

$42

$40

$45

Machine 2

$45

$42

$47

Machine 3

$40

$35

$54

Machine 4

$60

$30

$48

Machine 5

$45

$40

$45

Using the optimistic criterion, which alternative is best?

5. A plant manager considers the operational cost per hour of five machine alternatives. The cost per hour is sensitive to three potential weather conditions: cold, mild, and warm. The following table represents the operations cost per hour for each alternative-state of nature combination:

Alternatives

States of Nature

EMV

Weather related cost per hour

Cold cost/day

Mild cost/day

Warm cost/day

Machine 1

$42

$40

$45

Machine 2

$45

$42

$47

Machine 3

$40

$35

$54

Machine 4

$60

$30

$48

Machine 5

$45

$40

$45

Assume that for a randomly selected day, there is a 30% probability of cold weather, 50% probability of mild weather, and 20% probability of warm weather. What is the EVPI?

6. Barbour Electric is considering the introduction of a new product. This product can be produced in one of several ways: (a) using the present assembly line at a cost of $20 per unit, (b) using the current assembly line after it has been overhauled (at a cost of $5,000) with a cost of $18 per unit; and (c) on an entirely new assembly line (costing $20,000) designed especially for the new product with a per unit cost of $15. Barbour is worried, however, about the impact of competition. If no competition occurs, they expect to sell 10,000 units the first year. With competition, the number of units sold is expected to drop to 6,000. At the moment, their best estimate is that there is a 40% chance of competition. They have decided to make their decision based on the first year sales.

(a) Develop a decision table (EOL).

(b) What decision should they make?

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Explanation & Answer

Attached.

1. The following is a payoff table giving profits for various situations.
Alternative 1, since it has the least negative outcome (120).

2. The following is a payoff table giving profits for various situations.

The following are the probabilities to the states of nature.
P(A)= 03, P(B)= 0.5, P(C) =0.2
Compute the expected value for alternative l is as follows
E(Al )= (100)P(A)+ (120)P(B) +(180)P(C)
= (100)(03)+ (120)(0.5)+ (180)(0.2)
=30 +60 +36
=126
Compute the expected value for altemative 2 is as follows
E(Aq)=(120)P(A)+(140)P(B)+(120)P(C)
=(120)(o.3)+(140)(o.5)+(120)(o.2)
=36+70+21
=130
Compute the expected value for altemative 3 is as follows
E(As )= (200)P(A) +(100)P(B)+ (50)P(C)
= (200)(0.3)+ (100)(0.5) +(50)(0.2)
= 60 + 50 +10
= 120
We choose the decision with the largest expected value, which is A2 .
Thus, EMV* =130
Ifhe lcnewthat A was going to...


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