Sample Llm) daml F(w) 10 (deg) = ,-0. Wood short 0.122m m 10. 1962 P 14.2= 12° 10.00634 0.2943 30-5=25 0.3924 33-6-27 40_7=33 10.00586 0.3924 2 - 1 = 1 10.5886 4-1=3 0.7848 8-2=6° BAISA WOOD 10.4905 m 10.20m Iwood long G=40,000 lit li Brass 10.36 Themen Bruss hollow 0.981 Gum 6 0.006m 11 0.00lm 12 m Put 4mm 0.00 4m 15 11 10-comm 16 0.25 21 m 26 16 21 26 13-4=9' 3-1= 2 6-2=4° 13-8 = 5° 8° 6-3=3" To 5=5° 14-7-7° 17-8=9 2°-0 =2 3-0=3 4.0=4 Brass Solid 0.30m steel 31 15.0=5 =0.1962 OLE PL AE TL IPG ,-Q2 Ip= π de 32 (4m) O=IL ㅜ L Ip m Ip 0 GIP G T=FxR; R= 110 mm 0.11 on m Ip ALE PL A E 22-0, 1 Fe mg 2162X981 = 0.1962 1 Dog 0.04 0.05 $ != IL IG Ø AX T BALSA NORD 0.04 $= 4,- 4,-Q2 Ip = π de 0.06 0.08 32 Q.10 Т IL Ø G=40,000N L -> ㅋ ㅜ Im TL G= Ip un Ip G m. I - Lit Bruss GIP T=FxR; R=110mm=0.11. phizoud CVEN 207 3/28/18 Lab 5 Torsion: Determination of Shear Modulus The objective of this lab is to determine the shear modulus (G) for different materials due to torsional loading. In order to determine values for G, first you must measure the diameter of the rod in order to calculate lp and length of the rod between (L) the angular indicators after being loaded into the torsion apparatus. Then the angle of twist (0) between the indicators is measured as a function of applied force (F), collecting at least 4 data points. After converting mass-force to torque, generate a plot of angle of torque (T) vs. angle of twist ($) and use this to determine shear modulus and torsional stiffness/flexibility of the rods. Finally, compare your results to literature values and discuss any uncertainty and/or systematic error. G=BL o = TL GIP QIP πr4 2 at T = FXR, R=100mm Ip = πd4 32 = Gilla Submit: (EVERYONE should do their OWN analysis) 1) Table of measured and calculated values for •, F, T, and Ip. Plot your results of T (N*m, x-axis) vs. “(rad, y-axis) to determine G and include that plot below the table! Sample L, d, Ip F Slope T N*m ΔΦ 0 (deg) (rad) G calculated G literature (N) Wood P.1962 LEO:12 1 = 0.09634 short 10394 8299 bigos Wood L=0.20m 6.3927 2013 long d30.00386 p.3786 0.7898 9.981 4.1=3" 8-2=6 13-t=0" Brass GN 3-1- 영 2 hollow d=1.35 MM = 0.0138 d=2. 14 nm L=0.36 m IN 14-2010 A 13N CVEN 207 3/28/18 Brass solid Steel Solid 2) Theoretically, should G be different for samples of the same material but different length or cross- section? Why or why not? 3) Compare (rank) the shear modulus for the different material samples. 4) Compare your results to literature values for G-do they match? If not, is the expected trend in shear modulus for the materials demonstrated? 5) Comment on any uncertainty or systematic error that may have led to discrepancies with (4). *Bonus: Investigate why our wood values may not match literature. What is unique about wood?
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