t-tests and confidence intervals MUST HAVE GRAPH CALC

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penpxranepure2

Mathematics

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Below I will attach questions D, E, & F.

you need the answer to question D to answer E&F, I will also attach the answer to question D so that you can answer E&F.

YOU MUST HAVE A GRAPHING CALCULATOR to answer E&F, which is why I cannot answer. So please, kindly answer E&F showing all of your work

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D. Compute a 99% confidence interval for the difference between the time it takes you to get to school on the bus and the time it takes to go by car. Draw a conclusion about this difference based on this confidence interval using Ho :(4–42) = 0 as your null. (2 points) E. Construct the same confidence interval you did in part d, this time using your graphing calculator. Show what you do on your calculator, and what you put into your calculator, and give the confidence interval and degrees of freedom. (Hint: Go back to previous study materials for this unit if you need to review how to do this.)(2 points) F. How is the interval computed on a calculator different from the interval computed by hand? Why is it different? In this case, would you come to a different conclusion for the hypothesis Ho :(u-42) = 0 if you used the confidence interval generated by the calculator? (1 point) D. Compute a 99% confidence interval for the difference between the time it takes you to get to school on the bus and the time it takes to go by car. Draw a conclusion about this difference based on this confidence interval using as your null. (2 points Use : H.: (01 - 42 ) = 0 as your null Difference in mean between the two mean =11.30-9.06 = 2.24 19 x 2.39 +17 * 2.29 5.19 Pooled variance = 36 Va ast 1 1 5.49G) + 0.7613 Standard error = 18 20 Critical t-value at 99% CI=2.7195 Margin of error =0.7613*2.7195 =2.0704 99% CI = (5.49 2.0704) = (0.17, 4.31) As the confidence interval does not include therefore we can say that the null hypothesis is rejected as it does not contain the 0 in its interval.
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