Chit Test discussion

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xnryyrn

Mathematics

Description

Please see the attachment. They are posted as part A with questions and Part B with questions. Answer them thoroughly.

Please bid only if you are good in statistics or your major is in statistics.

This is due in 8 hours from now. Please bid only if you can provide answers within time.

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Explanation & Answer

See attached. Inform me if you need any edits

Chi Square distribution
Part A
1.
The expected number of absentees would be similar in all the days.
For each day, expected number = 805/5 = 161
The full table for expected values would be:
Mon
161

Tus
161

Wed
161

Thu
161

Fri
161

(Total)
805

2.
Null hypothesis: Number of absentees are similar in all the days
Alternate hypothesis: Number of absentees differ depending on the day.

The hypothesis is so because the test will aim to investigate if the observed frequencies differ
from the expected frequencies of the absentees bein...


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