Description
Please see the attachment. They are posted as part A with questions and Part B with questions. Answer them thoroughly.
Please bid only if you are good in statistics or your major is in statistics.
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Explanation & Answer
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Chi Square distribution
Part A
1.
The expected number of absentees would be similar in all the days.
For each day, expected number = 805/5 = 161
The full table for expected values would be:
Mon
161
Tus
161
Wed
161
Thu
161
Fri
161
(Total)
805
2.
Null hypothesis: Number of absentees are similar in all the days
Alternate hypothesis: Number of absentees differ depending on the day.
The hypothesis is so because the test will aim to investigate if the observed frequencies differ
from the expected frequencies of the absentees bein...