enginnering analysis

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Engineering

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i have hw due after 24 hours and i need your help and good work by following the steps on the file

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2018 Fall Semester ME 349 Engineering Analysis Homework, Part 4 Assigned: 09/11/18 Due: 09/20/18 Student__________________________CWID_____________________________________ For every problem, provide  The MATLAB script/function files that solve the problems.  Final answers. Run the prepared script/function file in the MATLAB command window in order to obtain the numerical values or plots.  Hardcopy of the report must include printed codes (scripts/functions), printed plots, and screenshots of MATLAB command window with numerical answers. Problem 1: Solve problem 2 on page 209 of Gilat’s book. Write a script that solves the problem. For (c), show results of the evaluation of every individual operator (= + >= > /) in the order of their evaluation. Problem 2: Solve problem 5 on page 210 of Gilat’s book. Write a script that solves the problem. For (d), show results of every individual operator (|‐ & ~*‐ |) in the order of their evaluation. Problem 3: Solve problem 15 on page 212 of Gilat’s book. Write a function that solves the problem. This function should have one input argument (x) and two output arguments (P and N) Problem 4: Write a script that solves problem 6 (a‐d) on page 210 of Gilat’s book. Problem 5: Write a function that solves problem 13 on page 211 of Gilat’s book with single input parameter m. Perform calculations with this function as requested.
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In fifth question, if you want to get the input from user (for m), then use this document as the answer. 😊 🍀

2018 Fall Semester
ME 349 Engineering Analysis
Homework, Part 4
Assigned: 09/11/18
Due: 09/20/18
Student__________________________CWID________________________________
Problem 1:
𝑎 = 6,

𝑏 = 2,

𝑐 = −5

a) 𝑦 = 𝑎 + 𝑏 > 𝑎 − 𝑏 < 𝑐
𝑦 = 6 + 2 > 6 − 2 < −5
𝑦 = 8 > 4 < −5
𝑦 = 8 > 4 & 4 < −5
𝑦 = 1 &0
𝒚=𝟎
b) 𝑦 = −6 < 𝑐 < −2
𝑦 = −6 < −5 < −2
𝑦 = −6 > −5 & − 5 < −2
𝑦 = 0 &1
𝒚=𝟎
c) 𝑦 = 𝑏 + 𝑐 ≥ 𝑐 > 𝑎/𝑏
𝑦 = 2 − 5 ≥ −5 > 6/2
𝑦 = −3 ≥ −5 > 3
𝑦 = −3 ≥ −5 & − 5 > 3
𝑦 = 1 &0
𝒚=𝟎
d) 𝑦 = 𝑎 + 𝑐 == ~(𝑐 + 𝑎 ~ = 𝑎/𝑏 − 𝑏)
𝑦 = 6 − 5 == ~(−5 + 6~ = 6/2 − 2)
𝑦 = 1 == ~(1 ~ = 3 − 2)
𝑦 = 1 ==...


Anonymous
Really useful study material!

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