Only need help with one question from my HW

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Mathematics

Description

This is a Linear Algebra question and I would like it to be written out in full and with as much detail as possible, so I can understand and then explain. I will attach a sceeen shot of it. Only question 4 is to be done. The rest of the questions are fine.

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.111 Sprint a 11:05 1 54% Done HW2 Name: Math 122 HW2 Sept 27 in class or in Moodle by Sept 28 at 7am EST Each question should be answered completely and clearly. Thus, you must set up the problem and matrix (if applicable). If you elect to row reduce with technology, then give the initial matrix and its row reduced echelon form, clearly indicating which is which in your write up. 1. Let ū - and we be the column vectors in R. (a) Determine the linear combination 37 - 2 + 4u. (b) Determine if the vector-1 ER is a linear combination of ū, ū, and 2. Is-1 e Span 6 >? Justify. 3. Consider the following 3 x 3 coefficient matrix A= 1 0 2 and a vector 6 in R. —3 2 10 3 (a) If possible, write the vector 5 as a linear combination of the columns of A. If this is not possible, then explain why (b) Will every vector y in Rbe able to be written as a linear combination of the column vectors of A? Explain your conclusion. 4. Show that the set of all polynomials of the form (a + bt|a, b € R} is a vector space with the operations (a+bt²)+(c + dt?) = (a + c) + (6 + d)t2 and kla+bt²) = ka+k6t2 for all k E R. Note that you must show that all 10 axioms hold.
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Explanation & Answer

Actually, I finished.I understand that it is NOT simple for you. But let's start from some specific axiom for which you have some doubts. After we'll make it clear, we'll proceed to other axioms.docx and pdf files are identical, use whatever you prefer

Note that these operations are quite natural for polynomials, so no doubt that the axioms
hold. Nevertheless, we need to prove this.
Let's start from the closedness axioms.
Addition: indeed, if 𝑣, 𝑤 ∈ 𝑉 then 𝑣 = 𝑣1 + 𝑣2 𝑡 2 , 𝑤 = 𝑤1 + 𝑤2 𝑡 2 , 𝑣1 , 𝑣2 , 𝑤1 , 𝑤2 ∈ ℝ.
Then by definition 𝑣 + 𝑤 = (𝑣1 + 𝑤1 ) + (𝑣2 + 𝑤2 )𝑡 2 which is indeed in 𝑉 because ℝ is
closed under addition.
Multiplication by a number: 𝑣 ∈ 𝑉 means 𝑣 = 𝑣1 + 𝑣2 𝑡 2 , by definition
𝑘𝑣 = (𝑘𝑣1 ) + (𝑘𝑣2 )𝑡 2 which is in 𝑉 because ℝ is closed under multiplication.

Now the numbered axioms.
1. �...


Anonymous
Really helpful material, saved me a great deal of time.

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