Description
Please solve the following in the pre lab.
1- part (e) in question 1.
2- Question 2 ( All parts)
3- Question 3 ( All parts)
In question 3, please use group number 1 and 2 in solving the problem.
You can solve the problems on a separate sheet. If you choose to hand write it, please use clear hand writing.
I will attach couple lectures that may help in solving the problems. The pre lab sheet is attached.
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Explanation & Answer
attached is my answer
Question 1:
With 1 = 60o , n2 1.5 , and t = 2 cm = 2 10−2 m , the distance d is calculated by:
cos 1
d = t sin 1 1 −
2
2
n
−
sin
2
1
cos 60o
−2
o
d = ( 2 10 m ) sin 60 1 −
1.52 − sin 2 60o
0.5
d = ( 0.02 )( 0.866 ) 1 −
1.52 − 0.8662
d = 0.01 m
Hence, the distance d is 0.01 m .
Question 2:
The indices of refraction of wavelengths 400 nm, 550 nm, and 700 nm are n1 = 1.47 , n2 = 1.46 ,
and n3 = 1.455 , respectively.
Let nair be the index of refraction of air and let i be the incident angle.
By Snell’s law, we ha...