MAT/116 Week 3 dq 1

In week 3, Section 2.4 of the text
discussed some mathematical formulas that are used in various fields to solve
problems in geometry.

Here’s a problem involving the
circumference and radius of a circle.

The equation for
circumference C in terms of radius
r is: C = 2pr.

Let’s assume the earth is a perfect
sphere and we tie a rope around the earth. The rope sits tightly on the surface
(circumference) of the earth.

Now let’s cut the rope and add 1
foot to it. (We’ve added 1 foot to the circumference.) The rope no longer sits
tightly on the earth, but is now some distance away from the surface.

Question: How far away from the
surface is the rope after we’ve added the foot to the circumference?  Or asking
another way-- when I add 1 foot to the circumference, what happens to the
radius? Show the equations and how they were used to solve this
problem.

( Note: No need to bring in the
distance around the earth which is 25000 miles. Just work with the equation for
circumference.)