# A problem on finding Standard Deviation

Mar 30th, 2015
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Create a set of 5 points that are very close together and record the standard deviation. Next, add a 6th point that is far away from the original 5 and record the new standard deviation.

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Create a set of 5 points that are very close together and record the standard deviation. Next, add a 6th point that is far away from the original 5 and record the new standard deviation.Answer:Let us consider the number of job applications made by 5 senior students before getting their first job. The number of applications made by the five students are 3,2,4,6 and 7. The mean M of the sample is given by M = ?(X)/NWhere ? = sum ofX = Individual data pointsN = number of data pointsHere, N = 5So, M = (2 +3+4+6+7)/5 = 22/5 = 4.4The standard deviation, S for a small sample size (such as 5 in this case) is given by the formulaS2 = ?(X-M)2 /N-1Where ? = Sum of X = Individual data points M = Mean of all data points N = number of data pointsX MX-M(X-M)224.4-2.45.7634.4-1.41.9644.4-0.40.1664.41.62.5674.42.66.76?(X-M)2 = 17.2S2 = ?

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