Incomplete combustion of carbon to CO, limiting reactant, percent yield and a problem on calorimetry

Apr 8th, 2015
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Balanced equation for combustion of carbon to CO, limiting reactant, percent yield and a problem on calorimetry

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1. The balanced equation is 2C + O2 ? 2CO2. The number of moles of C present 3. The number of moles of O2 present is 2.From the above equation in 1 we can see that 2 moles of C can produce 2 moles of CO. So 3 moles of C would produce 3 moles of CO.Again from the above equation in 1 we can see that 1 mole of O2 produces 2 moles of CO. So 2 moles of O2 would produce 4 moles of CO.The limiting reagent is the reagent that produces the least amount of product. In this case the limiting reactant is therefore C.3. Yield expected from 3 moles of C = (3* mol wt of CO) = 3* 28 = 84 g of CO

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