Physics: Momentum and Collisions

May 1st, 2015
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Aim: Based on the hypothesis and the given apparatus (no additional equipment can be added) plan and carry out a procedure to collect data to arrive a value for e .

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PhysicsBy chamesh CheckSkill testedMMORRTitleMarkAIMomentum and CollisionsPDAimBased on the hypothesis and the given apparatus (no additional equipment can be added) plan and carry out a procedure to collect data to arrive a value for e .TheoryNewtons Experimental Law states that the v2 v1 = e ( u2 u1 ) where 0 e 1 , where e = 0 for a perfectly inelastic collision and e = 1 for a perfectly elastic collision. For a body at height h0 the maximum height after each successive rebound can be predicted. When a body free falls through a height h0 , the speed which the ball approaches the ground which is stationary is given by the formula u2 u1 = 2 gh0 0Applying Newton's Experimental Law we have:e()2 gh0 0 = v2 0So we have that v2 = e 2 gh0The maximum height after the first rebound is given by h1 =2 gh0 e2h1 == e2 h02g(v2 22g)h2 = e 2 h1 = e2 e 2 h0 = e4 h0hn = e 2 hn 1 = e2( n1) h0To determine e in the lab hn and hn 1 could be measured for a series of measurements and graph plotted to get the best fit. Taking measurements of h while the ball bounces will be a difficult task and would lead to many points of error. A different approach will be taken. In this case mathematics will be employed to make the process simpler as it relates to taking this measurement as well as improve accuracy in determining a value for e . The first step is to recall the formula fo

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