# For the reaction A+3B=2C+D, initial mole of A is twice that of B. If at equilibrium moles of B and C

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For the reaction A+3B=2C+D, initial mole of A is twice that of B. If at equilibrium moles of B and C are equal, then percentage of B reacted is ?

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Answer on Question #51831, Chemistry, Physical ChemistryQuestion: For the reaction A+3B=2C+D, initial mole of A is twice that of B. If at equilibrium moles of B and C are equal, then percentage of B reacted is ?Answer:A+3B=2C+DTo solve this problem we need to make a table:A3B2CDInitial

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