IT 240 Week 4 CheckPoint TCP_IP LAN Plan

Feb 3rd, 2012
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IT 240 Week 4 CheckPoint TCP_IP LAN Plan I chose answer C. 255.255.240.0 based off of the fact the first octet is 150 and this determines it to be a class B address making it 255.255.0.0 and then for seven subnets you would need 4 bits to include the seven subnets. This leaves 4 bits in the third octet making it 255.255.240.0. I chose answer A. 255.255.255.192 because the network ID is a class C address making it a mask of 255.255.255.0. Take 2 bits from the last octet giving you a total of 4 subnets. This

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