Statistics Questions

Jul 20th, 2016
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Assuming that the distribution is normal for weight relative to the ideal and 99% of the male participants scored between (-53.68, 64.64), where did 95% of the values for weight relative to the ideal lie? Round you answer to two decimal places

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Exercise 181. Assuming that the distribution is normal for weight relative to theideal and 99% of the male participants scored between (-53.68, 64.64),where did 95% of the values for weight relative to the ideal lie? Roundyou answer to two decimal places.Using the standard normal distribution table, the mean of the weight is5.48 and the standard deviation is 22.93.x=5.48, SD=22.935.48+1.96(22.93) = 170.59925.48-1.96(22.93)=80.7136(80.71,170.60)x=5.48, SD=22.935.48+1.96(22.93) = 170.59925.48-1.96(22.93)=80.7136(80.71,170.60) Expressed as: (-39.46, 50.42)2. Which of the following values from Table 1 tells us about variabilityof the scores in a distribution?a) 60.22b) 11.94c) 22.57d) 53.663. Assuming that the distribution for General Health Perceptions isnormal, 95% of the females scores around the mean were betweenwhat values? Round your answer to two decimal places.From the standard normal distribution table, the mean = 39.71 and thestandard deviation = 25.4639.71 + 1.96(25.46) = 39.71 + 49.9 = 89.6139.71 - 1.96(25.46) = 39.71 - 49.9 = (-10.19)4. Assuming that the distribution of scores for Pain is normal, 95% ofthe mens scores around the mean

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