# suplimentary_solution_to_question

May 19th, 2015
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complete solution ...............worked out here.............................................................................................................................

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Given Co = 2, C1= 4, C2= 6 -> which are even numbers Ck = 5C(k-3) for k>=3 lets take k = 3, k=4, k=5, k=6 C3 = 5 C0 = 5(2) = 10 C4 = 5 C(4-3) = 5 C1 = 5(4) = 20 C5 = 5C2 = 5(6) = 30 C6 = 5 C3 = 5 (10) = 50 Finally we can conclude that all qualities Cn is even

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