Feb 3rd, 2012
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The document demonstrate how to use the conservation of mechanical energy to calculate the speed and the apparent weights of the rider at different locations. Each step is explain in great details.

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Using w= mg, mass of the passenger m = w/g = 474/9.8 = 48.4 kg.At B, the free body diagram isTmgwhere T is the apparent weight of the passenger, which is the force the track exerts to the passenger.At B, Newtons second law requires thatT mg = maIn order to calculate T we need to find a, at B and C the passenger is undergoing the uniform circularmotion, so a= v2/r, we know r =3m from the figure, so we need to find v, the speed of the passenger at B.This can be found by using the law of energy conversation,The total energy of the passenger at A, EA = 1/2mvA2 + mghAAt B, EB = 1

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