# statistics-determining t-critical value-z-critical value-constracting confidence interval,confidence

Feb 3rd, 2012
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Plastic bags used for packaging produce are manufactured so that the breaking strength of the bag is normally distributed with a mean of 5 pounds per square inch and a standard deviation of 1.5 pounds per square inch. A sample of 35 bags is selected. So we have that the breaking strength of the bags is normal with µ=5 lbs/in2 and σ = 1.5 lbs/in2. Also, n = 35. 1) What is the probability that the average breaking strength is between 5 and 5.5 pounds per square inch? 2) What is the probability that the average breaking strength is between 4.2 and 4.5 pounds per square inch? 3) What is the probability that the average breaking strength is less than 4.6 pounds per square inch? 4) Suppose you have selected a random sample of N-7measurements from a normal distribution. Compare the standard normal z- critical values with the corresponding t- critical values if you were forming the following confidence intervals: 480% confidence interval 6 more questions.........

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Plastic bags used for packaging produce are manufactured so that the breaking strength of the bag is normally distributed with a mean of 5 pounds per square inch and a standard deviation of 1.5 pounds per square inch. A sample of 35 bags is selected. So we have that the breaking strength of the bags is normal with =5 lbs/in2and ? = 1.5 lbs/in2. Also, n = 35.1) What is the probability that the average breaking strength is between 5 and 5.5 pounds per square inch?2) What is the probability that the average breaking strength is between 4.2 and 4.5 pounds per square inch?3) What is the probability that the average breaking strength is less than 4.6 pounds per square inch?4) Suppose you have selected a random sample of N-7measurements from a normal distribution. Compare the standard normal z- critical values with the correspondingt- critical values if you were forming the following confidence intervals: 480% confidence interval 590% confidence interval5) The following sample of 16 measurements was selected from a population that is approximately normally distributed. 91, 80, 99, 110, 95, 106, 78, 121, 106, 100, 97, 82, 100, 83, 115, 1046) Construct an 80% confidence interval for the population mean and interpret the interval.7) Construct a 95% confidence interval for the population mean and interpret the interval.8) Explain why the 80% confidence interval is narrower?A labor union has several thousand members. In a sample of 40 union members, 32 have ind

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